Ball out of play

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TurboAg
Posts: 45
Joined: Sun Mar 27, 2011 8:47 pm
Location: Houston, Texas

Re: Ball out of play

Post by TurboAg » Thu May 12, 2011 6:47 pm

CJoe, you are correct, it is 2 bases awarded for a throw OOB. Those bases are determined based either on when the ball was pitched or when thrown by the fielder. MLB Rule 7.05.g states:
MLB wrote:Each runner including the batter-runner may, without liability to be put out, advance— Two bases when, with no spectators on the playing field, a thrown ball goes into the stands, or into a bench (whether or not the ball rebounds into the field), or over or under or through a field fence, or on a slanting part of the screen above the backstop, or remains in the meshes of a wire screen protecting spectators. The ball is dead. When such wild throw is the first play by an infielder, the umpire, in awarding such bases, shall be governed by the position of the runners at the time the ball was pitched; in all other cases the umpire shall be governed by the position of the runners at the time the wild throw was made
.
Thus, in this case, it seems this was the first play by an infielder, thus awarded bases are determined from the time of the pitch. Thus the runner at 1st gets 2nd and 3rd, and the batter gets 1st and 2nd, which is 2 bases per runner.

Oh, and a throwing error on the SS, thus batter gets on base with E6.
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